Posted 2008-July-07, 14:24
we have to assume that declarer has 3=6=2=2 shape (his line looks odd, to me, with Qxx in clubs, not to even consider that partner may have defended differently with Ax.
We also need to assume that declarer lacks the spade Q and the diamond K.. either of these cards gives him his 8th trick.
We cannot afford to switch to a diamond, lest declarer hold Q10 and guesses correctly.
It looks easy enough to cash the king of clubs before playing the 3rd spade, so that partner can make declarer ruff, and then declarer is toast if he started with Jxx AKJxxx Q10 Qx or equivalent.
We need to eliminate declarer's second club, lest, in the endgame, we are forced down to Jx K or J KJ in the minors... declarer can then prevail, with Q10 of diamonds and a small club, if he reads the position.
We should have no trouble getting this right even if partner has Ax of clubs, and declarer made an interesting play at trick 3, and partner failed to get his club ruff..
Edit: just read phil's post, and point out that cashing the club K extracts the hypothetical 8 from declarer's hand, so kills that squeeze
'one of the great markers of the advance of human kindness is the howls you will hear from the Men of God' Johann Hari