( 1C ) - 1D - ( p ) - 1H = could be 4 or must be at least 5 cards ?
This post has been edited by TWO4BRIDGE: 2012-April-15, 12:02
Posted 2012-April-12, 19:58
This post has been edited by TWO4BRIDGE: 2012-April-15, 12:02
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the hog, on 2012-April-13, 18:03, said:
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daveharty, on 2012-April-13, 21:22, said:
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Antrax, on 2012-April-15, 07:17, said:
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TWO4BRIDGE, on 2012-April-15, 12:00, said:
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Zelandakh, on 2012-April-19, 02:28, said:
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Cyberyeti, on 2012-April-20, 06:03, said:
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Cyberyeti, on 2012-April-20, 06:03, said:
Zelandakh, on 2012-April-19, 02:28, said:
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S2000magic, on 2012-April-22, 11:37, said:
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Cyberyeti, on 2012-April-24, 06:23, said:
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S2000magic, on 2012-April-24, 19:28, said: