I am in a 6♣ contract and have no losers outside of trump suit.
Plenty of entries.
On the lead of a small ♣ from dummy RHO plays the 2 of ♣.
This leaves the AQ8 to be played. I figure that there are 8 ways they could be in opponents hands.
If LHO has AQ8 or AQ it makes no difference what I do because I will be down.
If LHO has Q8 or Q I need to play the K to make my contract
If LHO has A8 or A or 8 or Void I need to play the J[10] to make the contract.
Does this mean that there are only 6 way I should consider making the odds 4 to 2 {2 to 1] in favor of playing the J
or am I missing something?
Thank you