What kind of hand was your partner expecting for your weak two to put you in game?
OH well, 1
♠ loser, 1
♣ loser and 1
♦ loser for sure. You must avoid a second diamond and a second club. A tall order. The
♦Ace has to be on side. So you will play for that by a
♦ towards the king at some time. So it is how to avoid two loser in clubs. In isolation the odds favor leading the JACK and if covered, win ace and lead towards the queen. But you have a number of extra chances here.
For instance, against some players, you might try low
♣ to the 8, if WEST ducks the club from K9x(x) or Q9x(x) or KQ9(x) this works well. But a good player would not duck very often here, especially after you show up with the diamond king.
I think you just barely have the entries for an elimination play. Imagine, S-Q, diamond towards king, they win the ACE and lead a heart (if they duck diamond ACE it makes it easier for you). You win the King, cash diamond King, heart ace, diamond ruff, spade J, heart ruff. Now you have:
If either opponent has come to doubleton club, you can play A then x of clubs, playing him for Kx or Qx, they have no way to unblock (you will know this based upon number of clubs out... ). If you think the both kept three clubs, then you give power (finally) to the eight of clubs. You lead the CLUB JACK. If WEST covers, you win ACE and lead towards the TEN. IF WEST ducks, you let the jack "ride". A club has to come back, and now you have option of playing low from hand playing north for Q9x or K9x.
Ben